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1256=3.14x^2
We move all terms to the left:
1256-(3.14x^2)=0
We get rid of parentheses
-3.14x^2+1256=0
a = -3.14; b = 0; c = +1256;
Δ = b2-4ac
Δ = 02-4·(-3.14)·1256
Δ = 15775.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{15775.36}}{2*-3.14}=\frac{0-\sqrt{15775.36}}{-6.28} =-\frac{\sqrt{}}{-6.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{15775.36}}{2*-3.14}=\frac{0+\sqrt{15775.36}}{-6.28} =\frac{\sqrt{}}{-6.28} $
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